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The result over the **wavelength** range of interest (**to** ) is called Irradiance , in : (1) Since Watts are joules per second and the Planck-Einstein relation informs us that the energy of one **photon** is given by joules per **photon**, Equation (1) can be expressed as a **number** **of** **photons** per second per meter squared as follows (2).

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The number of photons per second are . Explanation: Given that, Wavelength = 650 nm. Power = 45 W. Distance R= 17 m. Diameter = 5.0 mm. We need to calculate the number of photon per second emitted by light bulb. Using formula of energy. The** power** is.** Put the value of E . Put the value into the formula.** We need** to calculate the surface area.**.

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The **photon** energy is E_ {p} = h\nu = \dfrac {hc} {\lambda} = hc\kappa E p = hν = λhc = hcκ where h \approx 6.626\cdot 10^ {-34} h ≈ 6.626 ⋅10−34 is the Planck constant and c c is the speed of light in vacuum.

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The light-gathering **power** is not a fixed **number**, but is expressed in comparison with another optical system, say your eye. Your pupil has a maximum size of about 0.5 cm, so the light-gathering **power** **of** an 8" telescope (diameter 20.3 cm) is. LGP = (20.3/0.5) 2 = 1650.

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E **photon** was calculated by (**Power** intensity*time of irradiation*wavelength)/(plank constant*light velocity). Now I would like to **calculate** total **number** **of** **photons** absorbed by sample (my sample.

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Lets try to find the **power** density of the "green light" This is in arbitrary units, but no matter, if you integrate it you get the total **power** **of** the lamp. My digit-oral-integrator says the total **power** under the curve is about 6000 nm13%. alpha kaden epub; elden ring blade of death build.

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Then, we can **calculate** the **number** **of** **photons** based on the relation between energy and **wavelength** **of** the light incident. Formula used: E = n h c λ. Complete answer: They've given that a sodium vapour lamp of 10 W converts 60% of the consumed energy into light. The **power** is the energy drawn per second.

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At least 48 **photons** are required for the synthesis of a single glucose molecule from CO 2 and H 2 O with a chemical potential. Methods: The energy in a mole of **photons** can be related to the **wavelength** **of** light by the following equation: where E is the energy in a mole of **photons**, N is Avogadro's **number** (6.02 x 10 23 **photons**.

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**4. Energy, Power, and Photons**Energy in a light wave Why we can often neglect the magnetic field Poynting vector and irradiance The quantum nature of light An electromagnetic wave in empty space The electric field, the magnetic- Apr 27, 2015. According to the equation E = n ⋅ h ⋅ ν (energy =
**number of photons**times Planck's constant times the frequency), if you divide the energy by Planck's constant, you should get**photons**per second. E h = n ⋅ ν → the term n ⋅ - The answer is 60. We assume you are converting between newton meter/minute and watt . The SI derived unit for
**power**is the watt . 1 N-m/min is equal to 0.016666666666667 watt . Note that rounding errors may occur, so always check the results. - Average
**power**is related to flux and**photon**energy by: P = F × E (equation 3) P = F × hc/ l (equation 4) P ( m W) = 1.989 × 10-10 × F / l (nm) (equation 5) For any given flux and**wavelength**(in nm), equation 5 can be used to**calculate**the corresponding - Pulsed laser: Pulse Energy (Joules) = Average
**Power**(Watts) / Repetition Rate (Hertz) Let's put some real values in there and assume that you are working with a laser that has a fixed 200 W output and a repetition rate that can be tuned from 20 Hz to 1 kHz. If you set the control at 20 Hz, we have 200 W / 20 Hz = 10 J per pulse.